The unsaturated ether on acidic hydrolysis produces carbonyl compounds as shown below: CH₃-CH=CH-O-CH=CH₂ → H₃…

Question

The unsaturated ether on acidic hydrolysis produces carbonyl compounds as shown below:

$$ \mathrm{CH_3-CH=CH-O-CH=CH_2}\ \xrightarrow{\ \mathrm{H_3O^{+}}\ }\ \mathrm{CH_3-CH_2-CH=O}\ \ 	ext{and}\ \ \mathrm{O=CH-CH_3} $$

Based on this, predict the solution/reagent that will help to distinguish "**P**" and "**Q**" obtained in the following reaction:

$$ \mathrm{CH_3-CH=CH-O-\underset{	extstyle |}{C}(CH_3)=CH_2}\ \xrightarrow[\Delta]{\ \mathrm{H_3O^{+}}\ }\ \mathrm{P}\ +\ \mathrm{Q} $$

Accepted Answer

C. Fehling solution

Answer

A. $$2,4	ext{-DNP}$$ reagent

Answer

B. Saturated $$	ext{NaHSO}_3$$ solution

Answer

D. Lucas reagent

Answer & step-by-step solution