When a light of a given wavelength falls on a metallic surface the stopping potential for photoelectrons is 3.…

Question

When a light of a given wavelength falls on a metallic surface the stopping potential for photoelectrons is $3.2 \, \text{V}$ . If a second light having wavelength twice of the first light is used, the stopping potential drops to $0.7 \, \text{V}$ . The wavelength of the first light is _____ $\text{m}$ .

A
$2.2 \times 10^{-8}$
B
$3.1 \times 10^{-7}$
C
$2.5 \times 10^{-7}$
D
$2.9 \times 10^{-8}$

Accepted Answer

C. $$2.5 	imes 10^{-7}$$

Answer

A. $$2.2 	imes 10^{-8}$$

Answer

B. $$3.1 	imes 10^{-7}$$

Answer

D. $$2.9 	imes 10^{-8}$$

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