MCQMediumJEE 2026Kirchhoff's Laws & Circuits

JEE Physics 2026 Question with Solution

The reading of the ammeter (AA) in steady state in the following circuit (assuming negligible internal resistance of the ammeter) is _____ AA.

  • A

    22

  • B

    12\dfrac{1}{2}

  • C

    00

  • D

    11

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: The ammeter reading in the circuit is required in steady state.

Find: The current through the ammeter.

In DC steady state, a capacitor behaves as an open circuit and does not allow current to pass through its branch.

Therefore, the diagonal branch containing the capacitor is effectively removed from conduction, and the remaining circuit is symmetrically arranged.

Because the resistances on both sides of the ammeter are identical, equal currents tend to flow through the ammeter in opposite directions.

Hence these equal and opposite currents cancel each other, so the net current through the ammeter is 00.

Therefore, the reading of the ammeter is 0A0 \, \text{A}. The correct option is C.

Symmetry Trick

Given: The circuit is in steady state and contains a capacitor.

Find: The ammeter reading.

Use two quick observations:

  1. In steady state, the capacitor branch is open.
  2. The remaining network is symmetric about the ammeter.

By symmetry, the potentials at the two ends of the ammeter become equal, so there is no potential difference across it.

Since

I=VRI = \frac{V}{R}

if V=0V = 0 across the ammeter, the current through it is also 00.

Therefore, the ammeter reads 0A0 \, \text{A}, so the correct option is C.

Common mistakes

  • Assuming the capacitor still conducts current in steady state. This is wrong because an ideal capacitor blocks DC after a long time. Treat the capacitor branch as an open circuit before analyzing the rest of the network.

  • Ignoring circuit symmetry after removing the capacitor branch. This is wrong because the ammeter lies between symmetric parts of the circuit, leading to equal and opposite current contributions. Check symmetry before applying lengthy calculations.

  • Thinking that the ammeter must show a non-zero current because it is physically connected in the circuit. This is wrong because current through an ammeter depends on the potential difference across it, which can be zero in a balanced symmetric network.

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