MCQMediumJEE Main 2026 · 24 January, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2026 · 24 January, Shift 2

Let the length of the latus rectum of an ellipse x2a2+y2b2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 (a>b)(a>b) be 3030. If its eccentricity is the maximum value of the function f(t)=34+2tt2f(t)=-\dfrac{3}{4}+2t-t^2, then (a2+b2)(a^2+b^2) is equal to

  • A

    276276

  • B

    516516

  • C

    256256

  • D

    496496

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