MCQMediumJEE 2026VSEPR Theory & Shapes of Molecules

JEE Chemistry 2026 Question with Solution

Given below are statements about some molecules/ions. Identify the CORRECT statements.

A. The dipole moment value of NF3\mathrm{NF_3} is higher than that of NH3\mathrm{NH_3}.

B. The dipole moment value of BeH2\mathrm{BeH_2} is zero.

C. The bond order of O22\mathrm{O_2^{2-}} and F2\mathrm{F_2} is same.

D. The formal charge on the central oxygen atom of ozone is 1-1.

E. In NO2\mathrm{NO_2}, all the three atoms satisfy the octet rule, hence it is very stable.

Choose the correct answer from the options given below:

  • A

    A, B, C, D & E

  • B

    B & C only

  • C

    B, C & D only

  • D

    A, C & D only

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Statements are given about dipole moment, bond order, formal charge, and octet rule for different molecules/ions.

Find: Which statements are correct and hence the correct option.

  1. Statement A: NH3\mathrm{NH_3} has a higher dipole moment than NF3\mathrm{NF_3} due to stronger NH\mathrm{N-H} bond polarity and vector addition. Therefore, statement A is false.

  2. Statement B: BeH2\mathrm{BeH_2} is linear and symmetrical, so its dipole moments cancel out. Therefore, its dipole moment is 00 and statement B is true.

  3. Statement C: Bond order of O22\mathrm{O_2^{2-}} is 11 and bond order of F2\mathrm{F_2} is also 11. Therefore, statement C is true.

  4. Statement D: In ozone (O3)\mathrm{(O_3)}, the central oxygen atom has a formal charge of 1-1. Therefore, statement D is true.

  5. Statement E: NO2\mathrm{NO_2} is an odd-electron molecule and does not satisfy the octet rule. Therefore, statement E is false.

Thus, the correct statements are B, C and D only, which corresponds to option C.

Conclusion: The correct option is C.

Statement-by-statement Evaluation

Given: Five statements about NF3\mathrm{NF_3}, NH3\mathrm{NH_3}, BeH2\mathrm{BeH_2}, O22\mathrm{O_2^{2-}}, F2\mathrm{F_2}, ozone, and NO2\mathrm{NO_2}.

Find: Evaluate each statement using molecular geometry and electron count.

The key checks are:

  • dipole moment depends on both bond polarity and molecular geometry,
  • bond order depends on electron distribution,
  • formal charge is obtained from Lewis structure,
  • octet rule must be checked from total valence electrons.

Applying these checks:

  • For NF3\mathrm{NF_3} and NH3\mathrm{NH_3}, NH3\mathrm{NH_3} has the higher dipole moment, so statement A is false.
  • BeH2\mathrm{BeH_2} is linear, therefore net dipole moment is zero, so statement B is true.
  • O22\mathrm{O_2^{2-}} and F2\mathrm{F_2} both have bond order 11, so statement C is true.
  • In ozone, the central oxygen carries formal charge 1-1, so statement D is true.
  • NO2\mathrm{NO_2} is an odd-electron species and does not satisfy the octet rule for all atoms, so statement E is false.

Therefore, only B, C and D are correct.

Conclusion: The correct option is C. Note that this also matches option (3) in the source listing.

Common mistakes

  • Assuming dipole moment depends only on bond polarity is incorrect because molecular shape and vector addition also matter. Always check geometry before comparing dipole moments.

  • Treating every molecule as octet-satisfying is wrong because odd-electron molecules such as NO2\mathrm{NO_2} are exceptions. Count total valence electrons before applying the octet rule.

  • Confusing option number with option label can cause marking errors. Here the correct statements are in option (3)\mathrm{(3)}, which maps to label C.

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