MCQMediumJEE Main 2026 · 24 January, Shift 1Cross Product

Mathematics Question from JEE Main 2026 · 24 January, Shift 1

Let a⃗=2i^+j^−2k^\vec a = 2\hat i + \hat j - 2\hat k, b⃗=i^+j^\vec b = \hat i + \hat j and c⃗=a⃗×b⃗\vec c = \vec a \times \vec b. Let d⃗\vec d be a vector such that ∣d⃗−a⃗∣=11|\vec d - \vec a| = \sqrt{11}, ∣c⃗×d⃗∣=3|\vec c \times \vec d| = 3 and the angle between c⃗\vec c and d⃗\vec d is π4\frac{\pi}{4}. Then a⃗⋅d⃗\vec a \cdot \vec d is equal to

  • A

    11

  • B

    33

  • C

    1111

  • D

    00

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