MCQMediumJEE Main 2026 · 24 January, Shift 1Applications of Integrals (Area)

Mathematics Question from JEE Main 2026 · 24 January, Shift 1

Let A1A_1 be the bounded area enclosed by the curves y=x2+2y=x^2+2, x+y=8x+y=8 and yy-axis that lies in the first quadrant. Let A2A_2 be the bounded area enclosed by the curves y=x2+2y=x^2+2, y2=xy^2=x, x=2x=2 and yy-axis that lies in the first quadrant. Then A1A2A_1-A_2 is equal to

  • A

    23(42+1)\dfrac{2}{3}(4\sqrt{2}+1)

  • B

    23(32+1)\dfrac{2}{3}(3\sqrt{2}+1)

  • C

    23(22+1)\dfrac{2}{3}(2\sqrt{2}+1)

  • D

    23(2+1)\dfrac{2}{3}(\sqrt{2}+1)

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