MCQMediumJEE Main 2026 · 23 January, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2026 · 23 January, Shift 2

Let PQ be a chord of the hyperbola x24y2b2=1\frac{x^2}{4} - \frac{y^2}{b^2} = 1, perpendicular to the xx-axis, such that OPQ is an equilateral triangle, O being the centre of the hyperbola. If the eccentricity of the hyperbola is 3\sqrt{3}, then the area of the triangle OPQ is

  • A

    115\frac{11}{5}

  • B

    95\frac{9}{5}

  • C

    835\frac{8\sqrt{3}}{5}

  • D

    232\sqrt{3}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Conic Sections (Parabola, Ellipse, Hyperbola) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions