Given: Least count is 0.01mm, pitch scale reading is 1mm, circular scale reading is 51, and the zero of the circular scale lies 3 divisions above the horizontal pitch line when the studs are in contact.
Find: The correct thickness of the sheet.
When the zero of the circular scale is above the reference line, the zero error is negative, so its magnitude is added to the observed reading.
The zero error is
Zero Error=−(3×0.01)=−0.03mm
The observed reading is
Measured Value=PSR+(CSR×LC)=1+(51×0.01)=1+0.51=1.51mm
Now apply zero correction:
Correct Thickness=Measured Value−Zero Error=1.51−(−0.03)=1.54mm
Therefore, the correct thickness of the sheet is 1.54mm. The correct option is B.