MCQEasyJEE 2026Vernier Calipers & Screw Gauge

JEE Physics 2026 Question with Solution

In a screw gauge, the zero of the circular scale lies 33 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is 1mm1 \, \text{mm} and the circular scale reading is 5151 then the correct thickness of the sheet is _____ mm\text{mm}. [Assume least count is 0.01mm0.01 \, \text{mm}]

  • A

    1.511.51

  • B

    1.541.54

  • C

    1.481.48

  • D

    1.501.50

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: Least count is 0.01mm0.01 \, \text{mm}, pitch scale reading is 1mm1 \, \text{mm}, circular scale reading is 5151, and the zero of the circular scale lies 33 divisions above the horizontal pitch line when the studs are in contact.

Find: The correct thickness of the sheet.

When the zero of the circular scale is above the reference line, the zero error is negative, so its magnitude is added to the observed reading.

The zero error is

Zero Error=(3×0.01)=0.03mm\text{Zero Error} = -(3 \times 0.01) = -0.03 \, \text{mm}

The observed reading is

Measured Value=PSR+(CSR×LC)=1+(51×0.01)=1+0.51=1.51mm\text{Measured Value} = \text{PSR} + (\text{CSR} \times \text{LC}) = 1 + (51 \times 0.01) = 1 + 0.51 = 1.51 \, \text{mm}

Now apply zero correction:

Correct Thickness=Measured ValueZero Error=1.51(0.03)=1.54mm\text{Correct Thickness} = \text{Measured Value} - \text{Zero Error} = 1.51 - (-0.03) = 1.54 \, \text{mm}

Therefore, the correct thickness of the sheet is 1.54mm1.54 \, \text{mm}. The correct option is B.

Common mistakes

  • Students often subtract 0.03mm0.03 \, \text{mm} because they see a zero error and assume every correction is subtraction. Here the zero is above the line, so the zero error is negative and its magnitude must be added to the measured value.

  • A common mistake is to use only the circular scale reading and forget the pitch scale reading. The measured value is PSR+(CSR×LC)\text{PSR} + (\text{CSR} \times \text{LC}), so 1mm1 \, \text{mm} must be included.

  • Some students treat 5151 as 0.51mm0.51 \, \text{mm} directly without multiplying by the least count explicitly. Always convert circular scale divisions using CSR×LC\text{CSR} \times \text{LC} before adding to the pitch scale reading.

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