Physics Question from JEE Main 2026 · 23 January, Shift 1

The de Broglie wavelength of an oxygen molecule at $27^\circ\text{C}$ is $x \times 10^{-12} \, \text{m}$. The value of $x$ is (take Planck's constant=$6.63 \times 10^{-34} \, \text{J/s}$, Boltzmann constant=$1.38 \times 10^{-23} \, \text{J/K}$, mass of oxygen molecule = $5.31 \times 10^{-26} \, \text{kg}$)