MCQMediumJEE Main 2026 · 23 January, Shift 1Continuity

Mathematics Question from JEE Main 2026 · 23 January, Shift 1

Let f(x)={ax2+2ax+34x2+4x3,x32,12b,x=32,12f(x) = \begin{cases} \frac{ax^2 + 2ax + 3}{4x^2 + 4x - 3}, & x \neq -\frac{3}{2}, \frac{1}{2} \\ b, & x = -\frac{3}{2}, \frac{1}{2} \end{cases} be continuous at x=32x = -\frac{3}{2}. If f(f(x))=75f(f(x)) = \frac{7}{5}, then xx is equal to :

  • A

    00

  • B

    22

  • C

    11

  • D

    1.41.4

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