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MCQEasyJEE Main 2026 · 22 January, Shift 1Rutherford's Model of Atom

Physics Question from JEE Main 2026 · 22 January, Shift 1

A 7.9 MeV7.9\, \text{MeV} α\alpha-particle scatters from a target material of atomic number 7979. From the given data, the estimated diameter of the nuclei of the target material is (approximately) _____ m\text{m}. [14πε0=9×109 N m2/C2 and electron charge =1.6×10−19 C]\left[\frac{1}{4\pi\varepsilon_0}=9\times10^9\, \text{N m}^2/\text{C}^2 \text{ and electron charge } =1.6\times10^{-19}\, \text{C}\right]

  • A

    1.69×10−121.69\times10^{-12}

  • B

    1.44×10−131.44\times10^{-13}

  • C

    2.88×10−142.88\times10^{-14}

  • D

    5.76×10−145.76\times10^{-14}

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