JEE Mathematics 2026 Question with Solution

Given: $A = \{x : |x^2 - 10| \le 6\}$ and $B = \{x : |x - 2| > 1\}$.

Find: Which set relation is correct.

For set $A$,

So,

Hence,

Therefore,

For set $B$,

This gives

So,

Therefore,

Now evaluate $B - A$. This means elements of $B$ that are not in $A$. The complement used in the solution is

Thus,

which gives

So,

Therefore, the correct option is C.

The solution also notes that option A is technically correct since

but the extracted solution concludes that option C is the correct representation.

From the solved sets,

Option A:

Since

we get

So this statement is true.

Option B:

Hence,

This is not equal to $[-4, -2] \cup [3, 4]$, so option B is false because $3 \notin B$.

Option C:

This matches the derived result, so option C is true.

Option D:

which simplifies to

This is not equal to $(-\infty, 1] \cup (2, \infty)$, so option D is false.

Thus, from the provided solution, the selected answer is C, even though option A also evaluates correctly.