Chemistry Question from JEE Main 2026 · 21 January, Shift 1

Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceed the activation energy of second reaction by $20 \, \text{kJ mol}^{-1}$. If $k_1$ and $k_2$ are the rate constants of first and second reaction respectively at $300 \, \text{K}$, then $\ln \frac{k_{2}}{k_{1}}$ will be _____. (nearest integer) [$R=8.3 \, \text{J K}^{-1} \text{ mol}^{-1}$]