Given: Two statements about magnetic properties of coordination compounds must be checked.
Find: Which option correctly identifies the truth values of Statement I and Statement II.
For each complex, determine the oxidation state, write the d-electron configuration, use ligand strength and geometry, and then count unpaired electrons.
Statement I
- [Cu(NH3)4]2+: Copper is +2, so Cu2+=3d9. A d9 system has 1 unpaired electron.
- [Ni(en)3]2+: Nickel is +2, so Ni2+=3d8. Octahedral complex with configuration t2g6eg2, so it has 2 unpaired electrons.
- [Ni(NH3)6]2+: Nickel is +2, so Ni2+=3d8. Octahedral complex with configuration t2g6eg2, so it also has 2 unpaired electrons.
- [Mn(H2O)6]2+: Manganese is +2, so Mn2+=3d5. With weak-field H2O in an octahedral high-spin complex, configuration is t2g3eg2, giving 5 unpaired electrons.
So the numbers of unpaired electrons are 1,2,2, and 5 respectively. Therefore, [Mn(H2O)6]2+ has the maximum number of unpaired electrons.
Statement I is true.
Statement II
Now examine the species in the given pairs.
- [NiCl4]2−: Nickel is +2, so 3d8. Since Cl− is a weak-field ligand, the complex is tetrahedral and has 2 unpaired electrons. Hence it is paramagnetic.
- [Ni(CO)4]: Nickel is in oxidation state 0. With strong-field CO, the metal attains paired electrons and the complex is diamagnetic.
- [Ni(CN)4]2−: Nickel is +2, so 3d8. Since CN− is a strong-field ligand, the complex is square planar and diamagnetic.
Check the pairs:
- {[NiCl4]2−,[Ni(CO)4]}: one paramagnetic and one diamagnetic, so not only diamagnetic.
- {[NiCl4]2−,[Ni(CN)4]2−}: one paramagnetic and one diamagnetic, so not only diamagnetic.
- {[Ni(CO)4],[Ni(CN)4]2−}: both are diamagnetic.
Thus, the number of pairs containing only diamagnetic species is one, not two.
Statement II is false.
Therefore, Statement I is true but Statement II is false.
The correct option is B.