NVAEasyJEE Main 2025 · 8 April, Shift 2Stoichiometry & Calculations

Chemistry Question from JEE Main 2025 · 8 April, Shift 2

20mL20 \, \text{mL} of sodium iodide solution gave 4.74g4.74 \, \text{g} silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value)

(Given : Na = 2323, I = 127127, Ag = 108108, N = 1414, O = 16g mol116 \, \text{g mol}^{-1})

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