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MCQMediumJEE Main 2025 · 8 April, Shift 2Inverse Trigonometric Functions

Mathematics Question from JEE Main 2025 · 8 April, Shift 2

The value of cot⁡−1(1+tan⁡2(2)−1tan⁡(2))−cot⁡−1(1+tan⁡2(12)+1tan⁡(12))\cot^{-1} \left( \frac{\sqrt{1 + \tan^2(2)} - 1}{\tan(2)} \right) - \cot^{-1} \left( \frac{\sqrt{1 + \tan^2 \left( \frac{1}{2} \right)} + 1}{\tan \left( \frac{1}{2} \right)} \right) is equal to:

  • A

    π−54\pi - \frac{5}{4}

  • B

    π−32\pi - \frac{3}{2}

  • C

    π+32\pi + \frac{3}{2}

  • D

    π+52\pi + \frac{5}{2}

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