MCQMediumJEE Main 2025 · 8 April, Shift 2Integration Techniques (Substitution, Parts, Partial Fractions)

Mathematics Question from JEE Main 2025 · 8 April, Shift 2

Let f(x)f(x) be a positive function and I1=1212xf(2x(12x))dxI_1 = \int_{-\frac{1}{2}}^1 2x \, f\left(2x(1-2x)\right) \, dx and I2=12f(x(1x))dx.I_2 = \int_{-1}^2 f\left(x(1-x)\right) \, dx. Then the value of I2I1\frac{I_2}{I_1} is equal to _____

  • A

    44

  • B

    66

  • C

    1212

  • D

    99

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Integration Techniques (Substitution, Parts, Partial Fractions) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions