NVAMediumJEE Main 2025 · 7 April, Shift 1Moment of Inertia & Radius of Gyration

Physics Question from JEE Main 2025 · 7 April, Shift 1

A, B and C are disc, solid sphere and spherical shell respectively with the same radii and masses. These masses are placed as shown in the figure.

Three equal circular bodies arranged in triangular contact: top disc A, lower left solid sphere B, lower right spherical shell C, with a vertical axis PQ passing through the top body and the midpoint between the two lower bodies.

The moment of inertia of the given system about PQ is x15I\frac{x}{15} I, where II is the moment of inertia of the disc about its diameter. The value of xx is:

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Moment of Inertia & Radius of Gyration questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions