MCQMediumJEE Main 2025 · 7 April, Shift 1Dot Product

Mathematics Question from JEE Main 2025 · 7 April, Shift 1

Let the angle θ, 0<θ<π2\theta, \ 0 < \theta < \frac{\pi}{2} between two unit vectors a^\hat{a} and b^\hat{b} be sin1(659)\sin^{-1} \left( \frac{\sqrt{65}}{9} \right). If the vector c=3a^+6b^+9(a^×b^)\vec{c} = 3\hat{a} + 6\hat{b} + 9(\hat{a} \times \hat{b}), then the value of 9(ca^)3(cb^)9(\vec{c} \cdot \hat{a}) - 3(\vec{c} \cdot \hat{b}) is:

  • A

    3131

  • B

    2727

  • C

    2929

  • D

    2424

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