MCQMediumJEE Main 2025 · 4 April, Shift 2Definite Integrals

Mathematics Question from JEE Main 2025 · 4 April, Shift 2

Let f(x)+2f(1x)=x2+5f(x) + 2f\left( \frac{1}{x} \right) = x^2 + 5 and 2g(x)3g(12)=x,  x>0.  If  α=12f(x)dx,  β=12g(x)dx, then the value of 9α+β is:2g(x) - 3g\left( \frac{1}{2} \right) = x, \; x > 0. \; \text{If} \; \alpha = \int_{1}^{2} f(x) \, dx, \; \beta = \int_{1}^{2} g(x) \, dx, \text{ then the value of } 9\alpha + \beta \text{ is:}

  • A

    11

  • B

    00

  • C

    1010

  • D

    1111

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