MCQHardJEE Main 2025 · 4 April, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2025 · 4 April, Shift 2

The center of a circle CC is at the center of the ellipse E:x2a2+y2b2=1E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, where a>ba > b. Let CC pass through the foci F1F_1 and F2F_2 of EE such that the circle CC and the ellipse EE intersect at four points. Let PP be one of these four points. If the area of the triangle PF1F2PF_1F_2 is 3030 and the length of the major axis of EE is 1717, then the distance between the foci of EE is:

  • A

    2626

  • B

    1313

  • C

    1212

  • D

    132\frac{13}{2}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Conic Sections (Parabola, Ellipse, Hyperbola) questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions