NVAMediumJEE Main 2025 · 4 April, Shift 1Ionic Equilibria & pH

Chemistry Question from JEE Main 2025 · 4 April, Shift 1

The pH of a 0.01M0.01 \, \text{M} weak acid HX\mathrm{HX} (Ka=4×1010)\left(\mathrm{K}_{\mathrm{a}}=4 \times 10^{-10}\right) is found to be 55 . Now the acid solution is diluted with excess of water so that the pH of the solution changes to 66 . The new concentration of the diluted weak acid is given as x×104M\mathrm{x} \times 10^{-4} \, \text{M}. The value of xx is _____ (nearest integer).

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