MCQEasyJEE 2025Escape Velocity

JEE Physics 2025 Question with Solution

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R. Assertion A: The kinetic energy needed to project a body of mass mm from earth surface to infinity is 12mgR\frac{1}{2} \mathrm{mgR}, where RR is the radius of earth. Reason R: The maximum potential energy of a body is zero when it is projected to infinity from earth surface.

  • A

    A False but R\mathbf{R} is true

  • B

    Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}

  • C

    A\mathbf{A} is true but R\mathbf{R} is false

  • D

    Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is NOT the correct explanation of A\mathbf{A}

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: Assertion says the kinetic energy needed to project a body of mass mm from the Earth's surface to infinity is 12mgR\frac{1}{2}mgR. Reason says the maximum potential energy of a body is zero at infinity.

Find: Which option correctly describes the truth of Assertion A and Reason R.

The gravitational potential energy at distance rr from the centre of the Earth is

U=GMmrU=-\frac{GMm}{r}

At infinity, gravitational potential energy becomes

U=0U=0

The minimum kinetic energy required to take the body from the Earth's surface to infinity is the escape energy:

K=12mve2K=\frac{1}{2}mv_e^2

where

ve=2GMRv_e=\sqrt{\frac{2GM}{R}}

Therefore,

K=GMmRK=\frac{GMm}{R}

Using

g=GMR2g=\frac{GM}{R^2}

we get

GM=gR2GM=gR^2

Hence,

K=gR2mR=mgRK=\frac{gR^2m}{R}=mgR

So the required kinetic energy is mgRmgR, not 12mgR\frac{1}{2}mgR. Therefore, Assertion A is false.

Now examine Reason R. Since gravitational potential energy is taken as zero at infinity, the statement that the maximum potential energy is zero at infinity is true.

Therefore, the correct conclusion is: Assertion A is false, but Reason R is true. The correct option is A.

Energy Interpretation

Given: A body starts from the Earth's surface and is projected to infinity.

Find: Whether the assertion value of kinetic energy is correct.

At the Earth's surface, the gravitational potential energy is

Us=GMmRU_s=-\frac{GMm}{R}

At infinity,

U=0U_\infty=0

So the increase in potential energy needed is

ΔU=UUs=0(GMmR)=GMmR\Delta U=U_\infty-U_s=0-\left(-\frac{GMm}{R}\right)=\frac{GMm}{R}

For the body to just reach infinity with zero final speed, the initial kinetic energy must equal this increase in potential energy:

K=ΔU=GMmR=mgRK=\Delta U=\frac{GMm}{R}=mgR

Thus the assertion value 12mgR\frac{1}{2}mgR is incorrect.

The reason is true because gravitational potential energy is indeed zero at infinity, but the assertion fails because the numerical value of the required kinetic energy has been written incorrectly.

Hence, Assertion A is false and Reason R is true, so the correct option is A.

Common mistakes

  • Using the orbital kinetic energy formula 12mgR\frac{1}{2}mgR in place of escape energy is incorrect. 12mgR\frac{1}{2}mgR is associated with satellite motion near the Earth's surface, whereas the energy needed to reach infinity is mgRmgR. Always use escape energy for projection to infinity.

  • Assuming that potential energy being zero at infinity directly makes the required kinetic energy 00 is wrong. Zero potential energy at infinity is only the reference value. You must calculate the increase in potential energy from the Earth's surface to infinity.

  • Forgetting the relation g=GMR2g=\frac{GM}{R^2} leads to incorrect conversion of GMmR\frac{GMm}{R} into terms of gg and RR. Substitute carefully to obtain GMmR=mgR\frac{GMm}{R}=mgR.

Practice more Escape Velocity questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.

Related questions