MCQMediumJEE Main 2025 · 4 April, Shift 1Dot Product

Mathematics Question from JEE Main 2025 · 4 April, Shift 1

Consider two vectors u=3i^j^\vec{u} = 3\hat{i} - \hat{j} and v=2i^+j^λk^\vec{v} = 2\hat{i} + \hat{j} - \lambda \hat{k}, λ>0\lambda > 0. The angle between them is given by cos1(527)\cos^{-1} \left( \frac{\sqrt{5}}{2\sqrt{7}} \right). Let v=v1+v2\vec{v} = \vec{v}_1 + \vec{v}_2, where v1\vec{v}_1 is parallel to u\vec{u} and v2\vec{v}_2 is perpendicular to u\vec{u}. Then the value v12+v22|\vec{v}_1|^2 + |\vec{v}_2|^2 is equal to

  • A

    232\frac{23}{2}

  • B

    1414

  • C

    252\frac{25}{2}

  • D

    1010

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