MCQEasyJEE Main 2025 · 3 April, Shift 2Capacitors & Dielectrics

Physics Question from JEE Main 2025 · 3 April, Shift 2

Using a battery, a 100pF100 \, \text{pF} capacitor is charged to 60V60 \, \text{V} and then the battery is removed. After that, a second uncharged capacitor is connected to the first capacitor in parallel. If the final voltage across the second capacitor is 20V20 \, \text{V}, its capacitance is : (in pF\text{pF})

  • A

    600600

  • B

    200200

  • C

    400400

  • D

    100100

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