MCQMediumJEE Main 2025 · 3 April, Shift 2Properties of Definite Integrals

Mathematics Question from JEE Main 2025 · 3 April, Shift 2

The integral 0π8xdx4cos2x+sin2x\int_{0}^{\pi} \frac{8x \, dx}{4 \cos^2 x + \sin^2 x} is equal to

  • A

    2π22\pi^2

  • B

    4π24\pi^2

  • C

    π2\pi^2

  • D

    3π22\frac{3\pi^2}{2}

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