MCQMediumJEE Main 2025 · 3 April, Shift 1Capacitors & Dielectrics

Physics Question from JEE Main 2025 · 3 April, Shift 1

A parallel plate capacitor is filled equally (half) with two dielectrics of dielectric constant ϵ1\epsilon_1 and ϵ2\epsilon_2, as shown in figures. The distance between the plates is dd and area of each plate is AA. If capacitance in first configuration and second configuration are C1C_1 and C2C_2 respectively, then C1C2\frac{C_1}{C_2} is:

Two capacitor configurations are shown. In the first, two dielectric slabs of constants epsilon one and epsilon two are stacked across half the separation each. In the second, the slabs occupy half the plate area each side by side.
  • A

    ϵ1ϵ2(ϵ1+ϵ2)2\frac{\epsilon_1 \epsilon_2}{(\epsilon_1 + \epsilon_2)^2}

  • B

    4ϵ1ϵ2(ϵ1+ϵ2)2\frac{4\epsilon_1 \epsilon_2}{(\epsilon_1 + \epsilon_2)^2}

  • C

    ϵ1ϵ2ϵ1+ϵ2\frac{\epsilon_1 \epsilon_2}{\epsilon_1 + \epsilon_2}

  • D

    ϵ0(ϵ1+ϵ2)2\frac{\epsilon_0 (\epsilon_1 + \epsilon_2)}{2}

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