The radiation pressure exerted by a light source on a perfectly reflecting surface placed at away from it, is :
- A
- B
- C
- D
The radiation pressure exerted by a light source on a perfectly reflecting surface placed at away from it, is :
Correct answer:C
Standard Method
Given: Power of source = , distance = , surface is perfectly reflecting.
Find: Radiation pressure on the surface.
For a perfectly reflecting surface,
where is the intensity and .
The intensity at distance from an isotropic source is
Substituting the given values,
So,
Now the radiation pressure is
Since ,
the solution works out , but it also states that the correct option is C, whose listed value is . This is a discrepancy in the source. Following the solution's declared correct option, the correct option is C.
Detailed Working and Source Discrepancy
Given: A light source and a perfectly reflecting surface at .
Find: The radiation pressure.
Thus the numerical result from the working is .
However, the solution's explicitly says "The Correct Option is C" and option C is . Therefore the source contains an internal inconsistency between its calculation and its listed answer. Using the page's declared option label, the answer is recorded as C.
Using instead of for a perfectly reflecting surface. Reflection reverses momentum, so the pressure is doubled compared with complete absorption.
Calculating intensity as or . The source is treated as radiating uniformly in all directions, so the power spreads over .
Missing the unit conversion that . Radiation pressure should be reported in pascals after evaluating the expression.
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