MCQMediumJEE Main 2025 · 3 April, Shift 1Linear Differential Equations

Mathematics Question from JEE Main 2025 · 3 April, Shift 1

Let gg be a differentiable function such that 0xg(t)dt=x0xtg(t)dt\int_0^x g(t) \, dt = x - \int_0^x t g(t) \, dt, x0x \ge 0 and let y=y(x)y = y(x) satisfy the differential equation dydxytanx=2(x+1)secxg(x)\frac{dy}{dx} - y \tan x = 2(x+1) \sec x g(x), x[0,π2)x \in \left[ 0, \frac{\pi}{2} \right). If y(0)=0y(0) = 0, then y(π3)y\left( \frac{\pi}{3} \right) is equal to](streamdown:incomplete-link)

  • A

    2π33\frac{2\pi}{3\sqrt{3}}

  • B

    4π3\frac{4\pi}{3}

  • C

    2π3\frac{2\pi}{3}

  • D

    4π33\frac{4\pi}{3\sqrt{3}}

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