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MCQEasyJEE 2025SI System & Derived Units

JEE Physics 2025 Question with Solution

Match List-I with List-II: List-I List-II

  • A

    (1) (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

  • B

    (2) (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

  • C

    (3) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  • D

    (4) (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: We are asked to match physical quantities with their SI units.

Find: The correct matching between List-I and List-II, and hence the correct option.

For each quantity:

(A) Heat capacity of a body:

Unit=JK=J K−1\text{Unit} = \frac{\text{J}}{\text{K}} = \text{J K}^{-1}

Hence, (A) →\to (II).

(B) Specific heat capacity of a body:

Unit=Jkg⋅K=J kg−1K−1\text{Unit} = \frac{\text{J}}{\text{kg} \cdot \text{K}} = \text{J kg}^{-1} \text{K}^{-1}

Hence, (B) →\to (III).

(C) Latent heat:

Unit=Jkg=J kg−1\text{Unit} = \frac{\text{J}}{\text{kg}} = \text{J kg}^{-1}

Hence, (C) →\to (I).

(D) Thermal conductivity:

Unit=Jm⋅s⋅K=J m−1K−1s−1\text{Unit} = \frac{\text{J}}{\text{m} \cdot \text{s} \cdot \text{K}} = \text{J m}^{-1} \text{K}^{-1} \text{s}^{-1}

Hence, (D) →\to (IV).

So the final matching is:

(A)→(II),(B)→(III),(C)→(I),(D)→(IV)(A) \to (II), \quad (B) \to (III), \quad (C) \to (I), \quad (D) \to (IV)

Therefore, the correct option is D.

Common mistakes

  • Confusing heat capacity with specific heat capacity is a common mistake. Heat capacity is for the whole body, so its unit is J K−1\text{J K}^{-1}, whereas specific heat capacity is per unit mass, so its unit is J kg−1K−1\text{J kg}^{-1} \text{K}^{-1}.

  • Treating latent heat as if it includes temperature change is incorrect. Latent heat refers to heat per unit mass during phase change, so the correct unit is J kg−1\text{J kg}^{-1}, not a unit containing K−1\text{K}^{-1}.

  • Writing the unit of thermal conductivity incompletely is incorrect. Thermal conductivity must include metre, second, and kelvin in the denominator, giving J m−1K−1s−1\text{J m}^{-1} \text{K}^{-1} \text{s}^{-1}.

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