MCQMediumJEE Main 2025 · 2 April, Shift 1Arithmetic Progression (AP)

Mathematics Question from JEE Main 2025 · 2 April, Shift 1

Let a1,a2,a3,a_1, a_2, a_3, \ldots be in an A.P. such that k=112a2k1=725a1\sum_{k=1}^{12} a_{2k-1} = -\frac{72}{5}a_1, a10a_1 \neq 0. If k=1nak=0\sum_{k=1}^{n} a_k = 0, then nn is:

  • A

    1111

  • B

    1010

  • C

    1818

  • D

    1717

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