Jeeify
MCQMediumJEE Main 2025 · 29 January, Shift 2Linear Differential Equations

Mathematics Question from JEE Main 2025 · 29 January, Shift 2

If for the solution curve y=f(x)y = f(x) of the differential equation

dydx+(tan⁡x) y=2+sec⁡x(1+2sec⁡x)2,x∈(−π2,π2),f(π3)=310,\frac{dy}{dx} + (\tan x)\, y = \frac{2 + \sec x}{(1 + 2\sec x)^2}, \qquad x \in \left(-\frac{\pi}{2}, \frac{\pi}{2}\right), \quad f\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{10},

then f(π4)f\left(\frac{\pi}{4}\right) is equal to:

  • A

    93+310(4+3)\frac{9\sqrt{3} + 3}{10\left(4 + \sqrt{3}\right)}

  • B

    3+110(4+3)\frac{\sqrt{3} + 1}{10\left(4 + \sqrt{3}\right)}

  • C

    5−322\frac{5 - \sqrt{3}}{2\sqrt{2}}

  • D

    4−214\frac{4 - \sqrt{2}}{14}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Linear Differential Equations questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Linear Differential Equations

Related questions