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MCQMediumJEE 2025Nomenclature (IUPAC & Common)

JEE Chemistry 2025 Question with Solution

Match List - I with List - II: List - I: StructureIUPAC Name\begin{array}{|c|c|} \hline \textbf{Structure} & \textbf{IUPAC\ Name}\end{array}

Table showing List I structures A to D alongside List II IUPAC names labeled I to IV for matching organic compounds.

Choose the correct answer from the options given below:

  • A

    (A)-(I), (B)-(II), (C)-(IV), (D)-(III)\text{(A)-(I), (B)-(II), (C)-(IV), (D)-(III)}

  • B

    (A)-(II), (B)-(I), (C)-(III), (D)-(IV)\text{(A)-(II), (B)-(I), (C)-(III), (D)-(IV)}

  • C

    (A)-(I), (B)-(III), (C)-(II), (D)-(IV)\text{(A)-(I), (B)-(III), (C)-(II), (D)-(IV)}

  • D

    (A)-(III), (B)-(I), (C)-(IV), (D)-(II)\text{(A)-(III), (B)-(I), (C)-(IV), (D)-(II)}

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: List - I contains organic structures and List - II contains their IUPAC names. Find: The correct matching between the structures and names.

From the solution working:

  • Structure (A) corresponds to 4-methylpent-1-ene, so (A)-(I).
  • Structure (B) corresponds to 4,4-dimethylheptane, so (B)-(III) as concluded in the primary solution.
  • Structure (C) corresponds to 3-ethyl-5-methylheptane, so (C)-(II) as concluded in the primary solution.
  • Structure (D) corresponds to 2-methyl-1,3-pentadiene, so (D)-(IV).

Thus, the correct matching is (A)−(I),(B)−(III),(C)−(II),(D)−(IV)(A)-(I), (B)-(III), (C)-(II), (D)-(IV).

Therefore, the correct option is C.

Matching Using IUPAC Nomenclature

Given: We must match each structure in List - I with the appropriate IUPAC name in List - II. Find: The option containing the correct correspondence.

Use the nomenclature rules: identify the longest carbon chain, give lowest locants to multiple bonds, and then assign substituent positions correctly.

The extracted solution states:

  1. (A) is 4-Methylpent-1-ene →\rightarrow (I)
  2. (B) is 4,4-Dimethylheptane
  3. (C) is 3-Ethyl-5-methylheptane
  4. (D) is 2-Methyl-1,3-pentadiene →\rightarrow (IV)

The final line of the solution explicitly concludes:

(A)−(I),(B)−(III),(C)−(II),(D)−(IV)\boxed{(A)-(I), (B)-(III), (C)-(II), (D)-(IV)}

There is an internal inconsistency in one detailed explanation block, but both the primary solution and the final boxed conclusion agree on (A)−(I),(B)−(III),(C)−(II),(D)−(IV)(A)-(I), (B)-(III), (C)-(II), (D)-(IV). Hence the correct option is C.

Common mistakes

  • Students often choose the wrong parent chain. This is incorrect because IUPAC naming must start from the longest valid carbon chain containing the multiple bond when present. Always identify the parent chain before naming substituents.

  • A common mistake is numbering the chain from the wrong end. This is wrong because double bonds must receive the lowest possible locant. Number the chain so that unsaturation gets priority over substituents.

  • Students may match names only by counting total carbons and ignore substituent positions. This is incorrect because compounds with the same carbon count can differ by substituent type and locant. Verify both the substituent names and their positions carefully.

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