MCQEasyJEE 2025Dimensions & Dimensional Analysis

JEE Physics 2025 Question with Solution

The pair of physical quantities not having same dimensions is:

  • A

    Torque and energy

  • B

    Pressure and Young's modulus

  • C

    Angular momentum and Planck's constant

  • D

    Surface tension and impulse

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: We need to identify the pair of physical quantities that do not have the same dimensions.

Find: The correct option.

Compare the dimensions of each pair:

  • Torque: [ML2T2][M L^2 T^{-2}]

  • Energy: [ML2T2][M L^2 T^{-2}] So, these have the same dimensions.

  • Pressure: [ML1T2][M L^{-1} T^{-2}]

  • Young's modulus: [ML1T2][M L^{-1} T^{-2}] So, these also have the same dimensions.

  • Angular momentum: [ML2T1][M L^2 T^{-1}]

  • Planck's constant: [ML2T1][M L^2 T^{-1}] So, these have the same dimensions.

  • Surface tension: [MT2][M T^{-2}]

  • Impulse: [MLT1][M L T^{-1}] These are different.

Therefore, the pair not having the same dimensions is Surface tension and impulse. The correct option is D.

The solution states option A, but the dimensional comparison shown in the working clearly proves that D is correct.

Direct Dimension Check

Given: A dimension comparison question.

Find: The mismatched pair.

A quick check shows that the first three pairs are standard equal-dimension pairs:

  • Torque and energy
  • Pressure and Young's modulus
  • Angular momentum and Planck's constant

For the last pair:

  • Surface tension =forcelength=[MT2]= \frac{\text{force}}{\text{length}} = [M T^{-2}]
  • Impulse =force×time=[MLT1]= \text{force} \times \text{time} = [M L T^{-1}]

Since these differ, the correct option is D.

Common mistakes

  • Confusing torque with a different quantity because it is rotational in nature. Torque and energy both have dimension [ML2T2][M L^2 T^{-2}]; the difference is physical meaning, not dimension. Always compare dimensions, not interpretation.

  • Assuming surface tension has the same dimension as force. Surface tension is force per unit length, so its dimension is [MT2][M T^{-2}], not [MLT2][M L T^{-2}]. Write the defining formula first.

  • Mistaking impulse for pressure or stress-type quantities. Impulse equals force multiplied by time, so its dimension is [MLT1][M L T^{-1}]. Use Impulse=FΔt\text{Impulse} = F \Delta t before comparing.

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