NVAMediumJEE Main 2025 · 29 January, Shift 1Inverse Trigonometric Functions

Mathematics Question from JEE Main 2025 · 29 January, Shift 1

Let S={x:cos1x=π+sin1x+sin1(2x+1)}S = \{ x : \cos^{-1}x = \pi + \sin^{-1}x + \sin^{-1}(2x+1) \}. Then xS(2x1)2\sum_{x \in S} (2x - 1)^2 is equal to:

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