NVAMediumJEE Main 2025 · 29 January, Shift 1Limits

Mathematics Question from JEE Main 2025 · 29 January, Shift 1

Let [t][t] be the greatest integer less than or equal to tt. Then the least value of pNp \in \mathbb{N} for which limx0+(x([1x]+[2x]++[px])x2([12x2]+[22x2]++[92x2]))1\lim_{x \to 0^{+}} \left( x \left( \left[ \frac{1}{x} \right] + \left[ \frac{2}{x} \right] + \cdots + \left[ \frac{p}{x} \right] \right) - x^2 \left( \left[ \frac{1^2}{x^2} \right] + \left[ \frac{2^2}{x^2} \right] + \cdots + \left[ \frac{9^2}{x^2} \right] \right) \right) \geq 1 is equal to:

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Limits questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions