Jeeify
MCQMediumJEE Main 2025 · 29 January, Shift 1Trigonometric Ratios & Identities

Mathematics Question from JEE Main 2025 · 29 January, Shift 1

Let MM and mm respectively be the maximum and the minimum values of

f(x)=∣1+sin⁡2xcos⁡2x4sin⁡4xsin⁡2x1+cos⁡2x4sin⁡4xsin⁡2xcos⁡2x1+4sin⁡4x∣,x∈Rf(x) = \begin{vmatrix} 1 + \sin^2 x & \cos^2 x & 4\sin 4x \\ \sin^2 x & 1 + \cos^2 x & 4\sin 4x \\ \sin^2 x & \cos^2 x & 1 + 4\sin 4x \end{vmatrix}, \quad x \in \mathbb{R}

Then M4−m4M^4 - m^4 is equal to:

  • A

    12151215

  • B

    10401040

  • C

    12951295

  • D

    12801280

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Trigonometric Ratios & Identities questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Trigonometric Ratios & Identities

Related questions