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MCQMediumJEE Main 2025 · 28 January, Shift 2Characteristics of EM Waves

Physics Question from JEE Main 2025 · 28 January, Shift 2

The magnetic field of an E.M. wave is given by: B⃗=(32i^+12j^)30sin⁡(ω(t−zc))\vec{B} = \left( \frac{\sqrt{3}}{2} \hat{i} + \frac{1}{2} \hat{j} \right) 30 \sin \left( \omega \left( t - \frac{z}{c} \right) \right) The corresponding electric field in S.I. units is:

  • A

    E⃗=(12i^+32j^)30csin⁡(ω(t+zc))\vec{E} = \left( \frac{1}{2} \hat{i} + \frac{\sqrt{3}}{2} \hat{j} \right) 30 c \sin \left( \omega \left( t + \frac{z}{c} \right) \right)

  • B

    E⃗=(34i^+14j^)30ccos⁡(ω(t−zc))\vec{E} = \left( \frac{3}{4} \hat{i} + \frac{1}{4} \hat{j} \right) 30 c \cos \left( \omega \left( t - \frac{z}{c} \right) \right)

  • C

    E⃗=(32i^−12j^)30csin⁡(ω(t+zc))\vec{E} = \left( \frac{\sqrt{3}}{2} \hat{i} - \frac{1}{2} \hat{j} \right) 30 c \sin \left( \omega \left( t + \frac{z}{c} \right) \right)

  • D

    E⃗=(12i^−32j^)30csin⁡(ω(t−zc))\vec{E} = \left( \frac{1}{2} \hat{i} - \frac{\sqrt{3}}{2} \hat{j} \right) 30 c \sin \left( \omega \left( t - \frac{z}{c} \right) \right)

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