Let be defined by and be defined by If both functions are onto and , then is equal to:](streamdown:incomplete-link)
- A
- B
- C
- D
Let be defined by and be defined by If both functions are onto and , then is equal to:](streamdown:incomplete-link)
Correct answer:A
Standard Method
Given: with and with . Both functions are onto.
Find: where .
For , find the range on .
So the critical points in the interval are and . Now evaluate:
Hence the minimum value is and the maximum value is , so
Therefore the integers in are , whose count is
Now consider for .
and as ,
Also, the function attains a positive maximum value less than , so the range includes and all other values lie below . Thus the only integer belonging to is .
Therefore,
and hence
Therefore, the correct option is A.](streamdown:incomplete-link)
Derivative-Based Range Analysis
Given: and are onto.
Find: The number of integers in .
For , use derivative to locate extrema:
Checking endpoint and critical-point values:
Since is continuous on the closed interval , its range is the full interval from minimum to maximum:
So the integers in are exactly through , giving
integers.
For , differentiate:
Thus the maximum occurs when
that is,
At that point the maximum value is positive but less than . Also . Hence
and the only integer in is .
So,
Therefore,
So the correct option is A.](streamdown:incomplete-link)
Taking the range of only from the endpoint values and is incorrect because a cubic can attain an interior maximum or minimum on the interval. Differentiate first and check the critical point as well.
Assuming and forgetting that is wrong. Since is attained, and must be counted in .
Counting integers in as is an endpoint-counting error. For inclusive integer counts, use , so the total is .
Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.