Let and If , , and the sum of the diagonal elements of is , where , then is:
- A
- B
- C
- D
Let and If , , and the sum of the diagonal elements of is , where , then is:
Correct answer:B
Standard Method
Given: and , where is an orthogonal matrix, so .
Find: The sum of diagonal elements of , written as , and then compute .
From
and
we get
Therefore, the sum of the diagonal elements of is the trace of :
The solution states The Correct Option is B and concludes that , although the intermediate working shown there is inconsistent with the matrix written in the question. Using the answer indicated by the solution, the correct option is B.
Therefore, the correct option is B.
Using orthogonal similarity
The key property is that for the rotation matrix ,
So the two successive transformations undo each other when substituted into .
Substitute into :
Hence the diagonal sum of equals the diagonal sum of . The provided the solution, however, explicitly marks B as the correct option. So the extracted answer is B, with the note that the displayed working on the page does not consistently match the question matrix.
Assuming one must multiply all matrices explicitly. This is unnecessary because is orthogonal and . Substitute into first and simplify before doing any long multiplication.
Using only trace invariance without first noticing that . While trace invariance is true, here the stronger identity makes the simplification immediate.
Trusting inconsistent intermediate working blindly. The solution contains a mismatch in the matrix entries and reasoning, so the algebra shown there should be checked against the original question before using it.
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