MCQMediumJEE 2025Viscosity of Liquids

JEE Physics 2025 Question with Solution

In the experiment for measurement of viscosity η\eta of a given liquid with a ball having radius RR, consider following statements: A. Graph between terminal velocity VV and RR will be a parabola. B. The terminal velocities of different diameter balls are constant for a given liquid. C. Measurement of terminal velocity is dependent on the temperature. D. This experiment can be utilized to assess the density of a given liquid. E. If balls are dropped with some initial speed, the value of η\eta will change.

  • A

    BB, DD and EE Only

  • B

    CC, DD and EE Only

  • C

    AA, BB and EE Only

  • D

    AA, CC and DD Only

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The experiment measures viscosity η\eta of a liquid using a ball of radius RR and terminal velocity VV.

Find: Which statements among A to E are correct.

Using Stokes' law, the terminal velocity is

V=29(ρsρl)gR2ηV = \frac{2}{9}\frac{(\rho_s-\rho_l)gR^2}{\eta}

So, VR2V \propto R^2.

  • A: Since VV is proportional to R2R^2, the graph of VV versus RR is a parabola. So A is correct.
  • B: Terminal velocity depends on the radius or diameter of the ball, so different diameter balls will not have the same terminal velocity. So B is incorrect.
  • C: Viscosity depends on temperature, and hence terminal velocity also depends on temperature. So C is correct.
  • D: If the density of the sphere, radius, viscosity, and terminal velocity are known, the density of the liquid can be obtained from the same relation. So D is correct.
  • E: Viscosity is a property of the liquid and does not change if the ball is given some initial speed. The ball eventually reaches terminal velocity. So E is incorrect.

Therefore, the correct statements are A, C and D only.

The solution concludes A, C and D only, which corresponds to option D in the given options, even though the answer key marks option B.

Statement-wise Analysis

Given:

V=29(ρsρl)gR2ηV = \frac{2}{9}\frac{(\rho_s-\rho_l)gR^2}{\eta}

where ρs\rho_s is the density of the sphere and ρl\rho_l is the density of the liquid.

Find: Evaluate each statement separately.

From the equation, terminal velocity varies as R2R^2, so the VV versus RR graph is parabolic. Thus A is true.

Because VV depends on R2R^2, changing the diameter changes the terminal velocity. Thus B is false.

Since viscosity η\eta changes with temperature, the measured terminal velocity also changes with temperature. Thus C is true.

Rearranging the formula,

ρl=ρs9ηV2gR2\rho_l = \rho_s - \frac{9\eta V}{2gR^2}

so the density of the liquid can be assessed if other quantities are known. Thus D is true.

Giving an initial speed does not alter the liquid property η\eta. It only affects the initial motion before terminal velocity is reached. Thus E is false.

Hence the correct set is A, C and D only, so the correct option is D.

Common mistakes

  • Assuming terminal velocity is the same for all balls in the same liquid. This is wrong because Stokes' law shows VR2V \propto R^2. Always check how terminal velocity depends on the ball radius or diameter.

  • Confusing a property of the liquid with the motion of the ball. Viscosity η\eta is a property of the liquid and does not change because the ball is given an initial speed. Distinguish between transient motion and material properties.

  • Ignoring temperature dependence. Since viscosity of liquids changes with temperature, terminal velocity measurements are temperature-sensitive. Always consider temperature control in viscosity experiments.

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