NVAHardJEE Main 2025 · 28 January, Shift 1Cross Product

Mathematics Question from JEE Main 2025 · 28 January, Shift 1

Let a=i^+j^+k^\vec{a} = \hat{i} + \hat{j} + \hat{k}, b=2i^+2j^+k^\vec{b} = 2\hat{i} + 2\hat{j} + \hat{k} and d=a×b\vec{d} = \vec{a} \times \vec{b}. If c\vec{c} is a vector such that ac=c\vec{a} \cdot \vec{c} = |\vec{c}|, c2a2=8\left|\vec{c} - 2\vec{a}\right|^2 = 8 and the angle between d\vec{d} and c\vec{c} is π4\frac{\pi}{4}, then 103bc+d×c2\left|10 - 3\,\vec{b} \cdot \vec{c}\right| + \left|\vec{d} \times \vec{c}\right|^2 is equal to:

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