MCQMediumJEE Main 2025 · 28 January, Shift 1Arithmetic Progression (AP)

Mathematics Question from JEE Main 2025 · 28 January, Shift 1

Let TrT_r be the rthr^{th} term of an A.P. If for some mm, Tm=125T_m = \frac{1}{25}, T25=120T_{25} = \frac{1}{20} and 20r=125Tr=1320\sum_{r=1}^{25} T_r = 13, then

5mr=m2mTr is equal to:5m \sum_{r=m}^{2m} T_r \text{ is equal to:}
  • A

    112112

  • B

    142142

  • C

    126126

  • D

    9898

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