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MCQMediumJEE Main 2025 · 24 January, Shift 2Aldehydes & Ketones

Chemistry Question from JEE Main 2025 · 24 January, Shift 2

Match List - I with List - II.

List - IList - II
(A) RCN→(ii) H3O+(i) SnCl2, HClRCHO\text{RCN} \xrightarrow[\text{(ii) } \text{H}_3\text{O}^+]{\text{(i) } \text{SnCl}_2,\ \text{HCl}} \text{RCHO}(I) Etard reaction
(B) C6H5COCl→Pd-BaSO4H2C6H5CHO\text{C}_6\text{H}_5\text{COCl} \xrightarrow[\text{Pd-BaSO}_4]{\text{H}_2} \text{C}_6\text{H}_5\text{CHO}(II) Gatterman-Koch reaction
(C) C6H5CH3→(ii) H3O+(i) CrO2Cl2, CS2C6H5CHO\text{C}_6\text{H}_5\text{CH}_3 \xrightarrow[\text{(ii) } \text{H}_3\text{O}^+]{\text{(i) } \text{CrO}_2\text{Cl}_2,\ \text{CS}_2} \text{C}_6\text{H}_5\text{CHO}(III) Rosenmund reduction
(D) C6H6→(ii) anhydrous AlCl3/CuCl(i) CO, HClC6H5CHO\text{C}_6\text{H}_6 \xrightarrow[\text{(ii) anhydrous } \text{AlCl}_3/\text{CuCl}]{\text{(i) CO, HCl}} \text{C}_6\text{H}_5\text{CHO}(IV) Stephen reaction

Choose the correct answer from the options given below:

  • A

    (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

  • B

    (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

  • C

    (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

  • D

    (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

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