MCQEasyJEE Main 2025 · 24 January, Shift 2Coulomb's Law & Superposition Principle

Physics Question from JEE Main 2025 · 24 January, Shift 2

A small uncharged conducting sphere is placed in contact with an identical sphere but having 4×108C4 \times 10^{-8} \, C charge and then removed to a distance such that the force of repulsion between them is 9×103N9 \times 10^{-3} \, N. The distance between them is (Take 14πϵ0=9×109\frac{1}{4\pi \epsilon_0} = 9 \times 10^9 in SI units):

  • A

    2cm2 \, cm

  • B

    4cm4 \, cm

  • C

    1cm1 \, cm

  • D

    3cm3 \, cm

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