NVAMediumJEE Main 2025 · 24 January, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2025 · 24 January, Shift 2

Let H1:x2a2y2b2=1H_1: \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 and H2:x2A2+y2B2=1H_2: -\frac{x^2}{A^2} + \frac{y^2}{B^2} = 1 be two hyperbolas having lengths of latus rectums 15215\sqrt{2} and 12512\sqrt{5} respectively. Let their eccentricities be e1=52e_1 = \sqrt{\frac{5}{2}} and e2e_2 respectively. If the product of the lengths of their transverse axes is 10010100\sqrt{10}, then 25e2225e_2^2 is equal to:

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