MCQMediumJEE Main 2025 · 24 January, Shift 2Conic Sections (Parabola, Ellipse, Hyperbola)

Mathematics Question from JEE Main 2025 · 24 January, Shift 2

If the equation of the parabola with vertex (32,3)\left( \frac{3}{2}, 3 \right) and the directrix x+2y=0x + 2y = 0 is αx2+βy2γxy30x60y+225=0\alpha x^2 + \beta y^2 - \gamma xy - 30x - 60y + 225 = 0, then α+β+γ\alpha + \beta + \gamma is equal to:

  • A

    77

  • B

    66

  • C

    88

  • D

    99

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