MCQMediumJEE Main 2025 · 24 January, Shift 2Inverse Trigonometric Functions

Mathematics Question from JEE Main 2025 · 24 January, Shift 2

If α>β>γ>0\alpha > \beta > \gamma > 0, then the expression cot1(β+1+β2αβ)+cot1(γ+1+γ2βγ)+cot1(α+1+α2γα)\cot^{-1}\left( \beta + \frac{1 + \beta^2}{\alpha - \beta} \right) + \cot^{-1}\left( \gamma + \frac{1 + \gamma^2}{\beta - \gamma} \right) + \cot^{-1}\left( \alpha + \frac{1 + \alpha^2}{\gamma - \alpha} \right) is equal to:

  • A

    3π3\pi

  • B

    π2(α+β+γ)\frac{\pi}{2} - (\alpha + \beta + \gamma)

  • C

    00

  • D

    π\pi

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